**Pythagoras' Theorem (in words):**

The square of the hypotenuse is equal to the sum of the squares of the other two sides.

**Pythagoras' Rule (in symbols):**

To find the hypotenuse **c ^{2} = a^{2} + b^{2}**

To find another side

*c* is always the hypotenuse.

Remember to find the *square root* in the last step.

**Pythagoras** was a 6^{th} century BC Greek philosopher, mathematician and founder of a religious cult named the **Pythagoreans** who believed in reincarnation.
He played an active role in the politics, but had to flee from his home when his teachings became unpopular. Now, he is best known for his
**Pythagorean Theorem** and **Pythagorean Triples**.

Here is a right triangle with sides of 3, 4 and 5.

Using areas of squares, you can see that 3^{2} + 4^{2} = 5^{2}

Does it work with other numbers?

Does Pythagoras' Rule work with the areas of shapes other than squares? Calculate the areas of these semi-circles. What do you notice?

Find the hypotenuse of a right-angled triangle whose perpendicular sides are 5 and 12.

**Answer:**

a = 5

b = 12

c^{2} = a^{2} + b^{2}

= 5^{2} + 12^{2}

= 25 + 144

= 169

c = √169 *(Remember to find the square root.)*

= 13

A carpenter building these stairs must calculate the **length of the supporting timber beam** underneath. The **vertical and horizontal
lengths are 200 cm and 210 cm**.

**Answer:**

a = 200

b = 210

c^{2} = a^{2} + b^{2}

= 200^{2} + 210^{2}

= 40000 + 44100

= 84100

c = √84100 *(Remember to find the square root.)*

= 290 cm

In a right-angled triangle, the **hypotenuse is 10**. **One side is 8**. What's the length of the **other side**?

**Answer:**

c = 10

b = 8

a^{2} = c^{2} – b^{2}

= 10^{2} – 8^{2}

= 100 – 64

= 36

a = √36

= 6

A skydiver, instead of falling directly downward, is blown by the wind as shown in the diagram. In the right triangle, the **hypotenuse is 26 metres**
and the **vertical fall is 24 metres**. What is the **horizontal distance** by which she will miss her landing target?

**Answer:**

c = 26 metres

b = 24 metres

a^{2} = c^{2} – b^{2}

= 26^{2} – 24^{2}

= 676 – 576

= 100

a = √100

= 10 metres off target

**Q1.** What is the **hypotenuse** of a right triangle whose perpendicular sides are 26 and 168?

**Q2.** Find the **other side** of a right triangle if the hypotenuse is 205 and one side is 45.

**Answers**
**A1.** 170
**A2.** 200

A regular hexagon has 6 equal sides. It can be divided into 2 equilateral triangles joined at the centre of the hexagon. If each side of the hexagon
has a length of 1 unit, prove that the **area of the hexagon is approximately 2.6 times the square of the side length**.